GMAT Focus Edition: Arithmetic sequences add a constant; geometric sequences multiply by a constant. Memorize the nth-term and sum formulas. Use $b-a+1$ to count integers.
Home โ€บ Course โ€บ Quantitative Reasoning โ€บ Lesson 17
Quantitative Reasoning • Lesson 17 of 20

Sequences &
Patterns Mastery

Arithmetic: $a_n = a_1 + (n-1)d$. Geometric: $a_n = a_1 r^{n-1}$. Count from $a$ to $b$: $b-a+1$. Sum of integers 1 to $n$: $n(n+1)/2$.

Time: 50 mins
Target: Q76 to Q88
Prerequisites: Lessons 1โ€“4
1

Arithmetic Sequences

An arithmetic sequence adds a constant difference $d$ between consecutive terms: $a, a+d, a+2d, \ldots$

nth Term
$a_n = a_1 + (n-1)d$
Sum of n Terms
$S_n = \dfrac{n(a_1 + a_n)}{2}$
Key Property: Mean = Median
For any arithmetic sequence, mean = median = average of first and last term.
Sequence {3, 7, 11, 15, 19}: mean = (3+19)/2 = 11 โœ“
2

Geometric Sequences

A geometric sequence multiplies each term by a constant ratio $r$: $a, ar, ar^2, ar^3, \ldots$

nth Term
$a_n = a_1 \cdot r^{n-1}$
Sum of n Terms
$S_n = a_1 \cdot \dfrac{r^n - 1}{r - 1}$
3

Sum Shortcuts for Consecutive Integers

SequenceSum
1 to $n$$\dfrac{n(n+1)}{2}$
Odd integers 1 to $2n-1$$n^2$
$a$ to $b$ (evenly spaced)$\dfrac{(b-a+1)(a+b)}{2}$
Count of integers from $a$ to $b$$b - a + 1$
4

GMAT Pattern Recognition

Cyclical Patterns

Units digits of powers cycle: $2^1=2, 2^2=4, 2^3=8, 2^4=16$ โ†’ cycle {2,4,8,6}. Use remainder when dividing by cycle length to find any term.

Custom Sequences

GMAT may define non-standard sequences recursively: $a_n = a_{n-1} + a_{n-2}$. Just follow the rule and build terms step by step.

5

10 Sequence Traps

1. nth term: it's $(n-1)d$, not $nd$

$a_n = a_1 + (n-1)d$. For the 5th term, use $d$ multiplied by 4, not 5.

2. Count of integers from $a$ to $b$: use $b-a+1$

From 3 to 9: $9-3+1 = 7$ integers. Many students say $9-3=6$.

3. Sum of arithmetic sequence: use mean ร— count

Mean = $(a_1+a_n)/2$. Sum = mean ร— number of terms.

4. Geometric ratio vs arithmetic difference

In geometric, you MULTIPLY. In arithmetic, you ADD. Don't mix them.

5. Careful with "every other" counting

Every 3rd integer from 1 to 100: count = $\lfloor 100/3 \rfloor = 33$ or $\lfloor (100-1)/3 \rfloor + 1$.

6. Cyclical patterns: divide index by cycle length

Units digit of $7^{53}$: cycle of 7 is {7,9,3,1} (length 4). $53 = 4 \times 13 + 1$. Remainder 1 โ†’ 1st position โ†’ 7.

7. Sum of first $n$ odd integers = $n^2$

This is a commonly tested fact: $1+3+5+\ldots+(2n-1)=n^2$.

8. Mean of arithmetic sequence = midpoint

For {4,7,10,13,16}: mean = $(4+16)/2 = 10$ = middle term. Always true for arithmetic sequences.

9. Recursive sequences: build step by step

Don't look for a shortcut in recursive sequences โ€” just compute each term.

10. Geometric sequence: terms could alternate sign

If $r < 0$, terms alternate between positive and negative. Check sign behavior.

6

10 GMAT Practice Questions

Q1 PS Difficulty: 600

The first term of an arithmetic sequence is 5 and the common difference is 3. What is the 20th term?

(C) 62. $a_{20} = 5 + (20-1)(3) = 5 + 57 = 62$.

Q2 PS Difficulty: 550

What is the sum of all integers from 1 to 50?

(B) 1275. $S = \frac{50(51)}{2} = \frac{2550}{2} = 1275$.

Q3 PS Difficulty: 650

In a geometric sequence, the first term is 2 and the common ratio is 3. What is the 5th term?

(C) 162. $a_5 = 2 \times 3^{5-1} = 2 \times 81 = 162$.

Q4 PS Difficulty: 550

How many integers are there from 15 to 84, inclusive?

(C) 70. Count = $84 - 15 + 1 = 70$.

Q5 PS Difficulty: 650

What is the sum of all even integers from 2 to 100?

(C) 2550. Even integers 2 to 100: 50 terms. Mean = $(2+100)/2 = 51$. Sum = $51 \times 50 = 2550$.

Q6 PS Difficulty: 700

A sequence is defined by $a_1 = 3$ and $a_n = 2a_{n-1} - 1$ for $n > 1$. What is $a_4$?

(D) 15. $a_1=3$. $a_2=2(3)-1=5$. $a_3=2(5)-1=9$. $a_4=2(9)-1=17$. Wait: $a_4=17$, which is choice (E). (E) 17 is correct.

Q7 PS Difficulty: 700

What is the units digit of $7^{42}$?

(A) 1. Units digits of $7^n$ cycle: 7, 9, 3, 1, 7, 9, 3, 1... (period 4). $42 = 4 \times 10 + 2$. Remainder 2 โ†’ 2nd position in cycle โ†’ 9. Wait, remainder 2 โ†’ second element = 9. (D) 9 is correct.

Q8 PS Difficulty: 600

What is the sum of the first $n$ positive odd integers?

(A) $n^2$. Sum of first $n$ odd integers: $1+3+5+\ldots+(2n-1)=n^2$. This is a classic identity.

Q9 DS Difficulty: 650

Is a sequence arithmetic?

(1) The difference between any two consecutive terms is 7.
(2) The sum of any three consecutive terms is divisible by 3.

(A) Statement (1) alone sufficient. (1): Constant difference of 7 between consecutive terms โ€” this IS the definition of arithmetic. Sufficient. (2): This is true for arithmetic sequences but also for other sequences. Not sufficient alone. Answer: (A).

Q10 PS Difficulty: 700

A geometric sequence has first term 5 and third term 20. What is the second term?

(B) 10. $a_3 = a_1 r^2$ โ†’ $20 = 5r^2$ โ†’ $r^2 = 4$ โ†’ $r = 2$. $a_2 = 5 \times 2 = 10$.

Lesson Summary — Key Takeaways

Arithmetic nth term: aโ‚ + (nโˆ’1)d

The 1st term plus $(n-1)$ times the common difference.

Count from a to b: bโˆ’a+1

3 to 9 inclusive = 9โˆ’3+1 = 7. The "+1" is always needed.

Sum = mean ร— count (arithmetic)

Mean of arithmetic sequence = (first + last)/2. Multiply by count for sum.

Cyclical units digits: divide by cycle length

Powers of 2 cycle {2,4,8,6}. Find remainder of exponent รท 4 to identify position.

← Lesson 16 Lesson 17 of 20 Lesson 18 →