GMAT Focus Edition: Percentages are the most common GMAT topic. Master the multiplier model and successive change formula to dominate this topic.
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Quantitative Reasoning • Lesson 3 of 20

Percentages &
Percent Change Mastery

Percent change = (New βˆ’ Old)/Old. Two successive changes multiply, never add. "Of" always means multiply. The original after a change = new Γ· multiplier.

Time: 55 mins
Target: Q78 to Q90
Prerequisites: Lesson 2 (Fractions & Ratios)
1

Percentage Fundamentals

A percentage is a fraction with denominator 100. "X percent of Y" always means $\frac{X}{100} \times Y$. The word "of" is multiplication.

The Percentage Triangle
Part
= Rate Γ— Whole
Rate
= Part Γ· Whole
Whole
= Part Γ· Rate
2

Percent Change Formula

Percent Change Formula
% Change = $\dfrac{\text{New} - \text{Old}}{\text{Old}} \times 100$
Positive = increase Β· Negative = decrease
Increase by X%
New = Old Γ— $\left(1 + \dfrac{X}{100}\right)$
20% increase β†’ multiply by 1.20
Decrease by X%
New = Old Γ— $\left(1 - \dfrac{X}{100}\right)$
30% decrease β†’ multiply by 0.70
3

Reverse Percentage (Finding the Original)

Given the final value after a percent change, find the original. Divide the final value by the multiplier.

Worked Example
After a 25% increase, the price is $125. What was the original?
Original Γ— 1.25 = 125
Original = 125 Γ· 1.25 = $100

Common Error: After a 25% increase, many students subtract 25% from the new value to get the original. That gives $93.75, NOT $100. Always divide by the multiplier.

4

Compound & Successive Percentage Changes

When two percentage changes are applied successively, they do NOT simply add. The combined effect is multiplicative.

Successive: $P \times (1+r_1) \times (1+r_2)$
+20% then βˆ’20% β‰  0%. Actual: $1.20 \times 0.80 = 0.96$ β†’ net βˆ’4%
Shortcut: Successive change formula
Net % = $a + b + \dfrac{ab}{100}$
+20% then βˆ’20%: $20 + (-20) + \frac{20(-20)}{100} = 0 - 4 = -4\%$ βœ“
5

10 Percentage Precision Traps

1. Reverse percentage error

After X% increase, the original is NOT (new βˆ’ X% of new). Divide by (1 + X/100).

2. Percent of what base?

"Sales increased 20%" β€” 20% of what? Always identify the base clearly.

3. Successive changes add trap

+30% then βˆ’30% β‰  0%. The net is always negative: βˆ’9% in this case.

4. "More than" vs "% of"

X is 20% more than Y means X = 1.2Y, not X = 0.2Y.

5. Percentage point vs percent change

Rates going from 10% to 15% is a 5 percentage point increase but a 50% relative increase.

6. Part of wrong whole

Percent discount is always on original price, not sale price. Percent tip is on pre-tax amount.

7. Double-counting in overlaps

When given A and B percentages, those who are in both must not be counted twice.

8. 100% of something β‰  doubling sometimes

If X increases by 100%, X doubles. If X decreases by 100%, X becomes 0.

9. Population/sample confusion

A percentage from a sample doesn't necessarily apply to the whole population without more info.

10. Mixture percentages

When combining two groups with different percentages, the combined percentage is a weighted average, not a simple average.

6

10 GMAT Practice Questions

Q1 PS Difficulty: 650

A jacket originally costs $\$80$. It is first discounted by 25%, and then the discounted price is increased by 10%. What is the final price?

(D) $66. Step 1: 25% off β†’ $80 Γ— 0.75 = $60. Step 2: 10% increase β†’ $60 Γ— 1.10 = $66.

Q2 PS Difficulty: 600

After a 40% increase, a machine costs $\$2,100$. What was its original cost?

(C) $1,500. Original Γ— 1.40 = 2100 β†’ Original = 2100 Γ· 1.40 = $1,500.

Q3 PS Difficulty: 700

Last year, a company's revenue was $\$500{,}000$. This year, revenue increased by 20% in Q1 and then decreased by 20% in Q2. What is the revenue after both changes?

(A) $480,000. $500,000 Γ— 1.20 = $600,000. Then $600,000 Γ— 0.80 = $480,000. Net change = βˆ’4% (not 0%). Using formula: $20 + (-20) + \frac{20Γ—(-20)}{100} = -4\%$. $500,000 Γ— 0.96 = $480,000.

Q4 PS Difficulty: 650

In a survey, 60% of respondents preferred Product A and 50% preferred Product B. If 20% preferred both, what percentage preferred neither?

(C) 10%. By inclusion-exclusion: AβˆͺB = 60 + 50 βˆ’ 20 = 90%. Neither = 100 βˆ’ 90 = 10%.

Q5 PS Difficulty: 550

A student's test score increased from 60 to 75. By what percent did the score increase?

(C) 25%. % Change = (75βˆ’60)/60 Γ— 100 = 15/60 Γ— 100 = 25%.

Q6 PS Difficulty: 600

If 35% of $x$ equals 42, what is 60% of $x$?

(B) 72. $0.35x = 42$ β†’ $x = 120$. 60% of 120 = $0.60 Γ— 120 = 72$.

Q7 DS Difficulty: 700

Is the percent increase from $a$ to $b$ greater than 50%?

(1) $b = a + 20$
(2) $a < 40$

(C) BOTH together sufficient. % increase = 20/a Γ— 100 > 50% means a < 40. (1) alone: gives bβˆ’a=20 but without knowing a we can't determine the percentage. (2) alone: a<40 but we don't know bβˆ’a. Together: if b = a+20 AND a < 40, then 20/a > 20/40 = 50%. Sufficient.

Q8 PS Difficulty: 650

A store marks up items by 40% and then offers a 20% discount. What is the overall percent change from the original price?

(D) +12%. Using the successive change formula: $40 + (-20) + \frac{40(-20)}{100} = 20 - 8 = 12\%$ increase.

Q9 PS Difficulty: 600

What is 15% of 80% of 250?

(C) 30. 80% of 250 = 200. 15% of 200 = 30. Alternatively: 0.15 Γ— 0.80 Γ— 250 = 0.12 Γ— 250 = 30.

Q10 PS Difficulty: 750

Last year, expenses were $\$4{,}000$ and profit was 20% of expenses. This year, expenses rose 25% and profit remained the same absolute amount. What is this year's profit as a percent of this year's expenses?

(C) 16%. Last year's profit = 20% Γ— $4,000 = $800. This year's expenses = $4,000 Γ— 1.25 = $5,000. Profit % = 800/5000 Γ— 100 = 16%.

Lesson Summary — Key Takeaways

% Change = (Newβˆ’Old)/Old Γ— 100

The direction of change (+ or βˆ’) is captured by the sign of the result.

Increase/decrease are multipliers

+25% β†’ Γ—1.25; βˆ’30% β†’ Γ—0.70. Build multiplicative chains for successive changes.

Reverse: divide by multiplier

After X% increase, original = final Γ· (1 + X/100). Never subtract X% from final.

Inclusion-exclusion for overlaps

AβˆͺB = A + B βˆ’ A∩B. Use this for "both/neither" problems.

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